Hi,
I need to construct a dome in balsa wood with a 55cm diameter. It cannot exceed 12.5cm in height, should be supported by 4 or more stanchions(total height[stanchion+dome] cannot exceed 20cm)and should be able to withstand a weight of at least 15kg and weigh less than 80g.
I would like to build a geodesic dome to fulfill this assignment. However, the height of a 2v 55cm diameter dome would be its radius i.e. 27.5cm, thus exceeding the authorised maximum.
I have considered building a dome with a bigger diameter and keeping only the "top part" of the dome which would correspond to the dimensions I need. Is this wise? If so, how do I readapt the chord factor - as the triangles will have to be redimensioned - and in general any other calculation?
Thank you
[ Comments 2 ]
posted by
simon
13/03/2011 00:26:04
I'm not sure how that's going to work. The base of the dome needs to be fixed to the ground to give the dome its stability. If it was to sit on a trianulated skirt that would do it, but I don't think it could just sit on straight legs. Anyways, the struts for a flattened 2v dome 55 accross and 12.5 high would be (and this would be easier with a picture but I can't post the link) top pentagon: spokes 14.578, rim 16.996, 5 other pentagons: bottom strut 16.996, lower two rim struts 11.092, top two rim struts 15.017, top spoke 11.324, upper two spokes 14.906, lower two spokes 10.290. and the other 5 struts around the base 16.996.
posted by
tmm
17/03/2011 16:23:01
Sorry for the late reply. Thanks a lot for your time and help! I'll look into this right away.